What is the molarity (concentration) of 2.53 L of NaOH which exactly neutralizes 5.0L of 1.25 M HCl?

The concentration of NaOH is 2.47 M

Explanation:

The equation of the reaction is

HCl (aq) + NaOH(aq) > NaCl(aq) + H2O(l)

Given;

Concentration of acid CA= 1.25 M

Volume of acid VA= 5.0L

Concentration of base CB=

Volume of base VB= 2.53 L

Number of moles of acid NA= 1

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CB= CAVANB/VBNA

CB= 1.25 × 5.0 ×1 / 2.53×1

CB= 2.47 M

Therefore the concentration of NaOH is 2.47 M

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

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