At a given temperature, Kc=1.3x10-2 for reaction 1. What is the value of Kc for reaction 2? Reaction 1: begin mathsize 12px style N subscript 2 open parentheses g close parentheses plus 3 H subscript 2 open parentheses g close parentheses rightwards harpoon over leftwards harpoon 2 N H subscript 3 open parentheses g close parentheses end style Reaction 2: begin mathsize 12px style 4 N H subscript 3 open parentheses g close parentheses rightwards harpoon over leftwards harpoon space 2 N subscript 2 open parentheses g close parentheses plus 6 H subscript 2 open parentheses g close parentheses end style

See explaination

Explanation:

For a reversible reaction, the equilibrium constant for a backward reaction is reciprocal.

If the coefficients in a balanced equation are multiplied by a factor, n, the equilibrium expression is raised to the nth power.

K' = (K)^n

In the second reaction the value kf n is 2. The first reaction is multiplied by 2.

See attachment for further solution

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2