After the end of a normal inspiration, the volume of air in the lungs is about 2.8 L. Normally quiet inspiration is driven by a pressure difference of about 2 mm Hg. The air in the lungs is at 37C and after normal expiration it is at atmospheric pressure. Quiet inspiration is driven by the expansion of the chest cavity by contraction of the diaphragm, which expands the air in the lungs. How much is the air expanded to produce an decrease of 2 mmHg in pressure

The Volume of the lungs that would produce 2 mmHg pressure decrease is

Explanation:

From the question we are told that

     The volume of air in the lungs is  

     The pressure difference for quit normal inspiration is

      The temperature of air in the lungs

      The pressure  after normal  expiration is at  

From ideal gas law we have that

Now since  nRT is constant we have that

As the pressure decreased by 2 mmHg the volume becomes

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