A solution has a22.0*10^-6 H30^+ Calculate the OH^- and pH of this solution, be sure to show work.

pH= 4.66

OH^- = 4.55*10^-10

Explanation:

So H3O^+ means the same thing as [H^+].

so pH= -log(22.0*10^-6)

pH= 4.66

To find [OH^-]

[H^+] [OH^-] = 1*10^-14

1*10^-14 / 22.0*10^-6 = 4.55*10^-10= OH^-

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.