Does the coronavirus have DNA or RNA?

The coronavirus has RNA?

Explanation:

Coronaviruses are important human and animal pathogens and contain an extraordinarily long (27-31 kb) RNA genome. Its RNA synthesis involves complex mechanisms of regulation, similar to those of DNA viruses. In this treatise, mouse hepatitis virus (MHV) is used as a model for the discussion of the mechanism of viral RNA synthesis. We show that MHV RNA synthesis requires interactions of multiple RNA components, which are likely mediated by protein-RNA and protein-protein, as well as RNA-RNA, interactions. This virus also provides a unique example of a discontinuous transcription mechanism, which involves a trans-acting RNA component. Finally, study of the cis-acting signals for the various steps of RNA synthesis revealed an insight into the regulation of viral RNA synthesis. This discussion suggests that the regulation of RNA synthesis in coronavirus is more complex than previously thought possible for RNA viruses. Coronavirus RNA transcription and replication may serve as a paradigm of RNA synthesis for RNA viruses in general.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

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