Chemistry, 15.04.2020 03:02 beauburgess1108
Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride?
Ti(s) + 2 Cl2(g) →
TiCl4(l)
ΔH = –804.2 kJ/mol
TiCl4(g) → 2 Cl2(g) +
Ti(s)
ΔH = 763.2 kJ/mol
Answers: 1
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