5. A student is trying to identify a metal unknown. The student performs a calorimetry experiment similar to this week’s lab. The metal was heated to 115.0°C and placed in a calorimeter where it cooled to 32.6°C. The amount of heat released by 25.0g of the metal was 63.5 cal Calculate the specific heat of the metal and determine its identity by looking at the specific heat values in page 239 of your textbook. (Keep track of units!).

This metal could be lead

Specific heat = 0.0308 cal/g°C

Explanation:

Step 1: Data given

The metal was heated to 115.0°C

in a calorimeter where it cooled to 32.6°C.

Mass of the metal = 25.0 grams

Heat released = 63.5 cal

Step 2: Calculate the specific heat of the metal

Q = m*c*ΔT

⇒with Q = the heat released = 63.5 cal

⇒with m = the mass of the metal = 25.0 grams

⇒with ΔT = the change of temperature = T2 - T1 = 32.6 °C - 115.0°C = -82.4 °C

⇒ c = the specific heat = TO BE DETERMINED

63.5 = 25.0 * c * 82.4

C = 0.0308 cal/g°C

This metal could be lead

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

the answer is c

tell me if wrong