80.0 grams of NaOH is dissolved in water to make a 6.00 L
solution. What is the molarity of the solution? (Molar mass of
NaOH = 40.0 g/mol) _M

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of sodium hydroxide solution (NaOH) = 80.0 grams

Gram molecular mass of sodium hydroxide solution (NaOH) = 40.0 gram/mole

volume of the solution (v) = 6.00 L = 6000 ml

To find:

molarity of the solution (m)

We know,

m =

where,

m represents the molarity of the solution

n represents the no of moles

v represents the volume of the solution

we also know;

n =

where,

m represents the mass of the sodium hydroxide

M represents the Gram molar mass of the solution

So,

n =

n = 2

So,

m =  

m = 3 × M

Therefore the molarity of the solution is 3 × M.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.