Solve 2a² and 3b²-c³ if A=3 ,B=2 ,C=1

Since we know a = 3, substitute this into the expression:

2a² = 2 x 3²

3² = 9

So 2a² = 2 x 9

2a² = 18

We know b = 2 and c = 1, so substitute these values into the expression:

3b² - c³ = 3 x 2² - 1³

2² = 4
1³ = 1

So:

3 x 4 - 1

Using the order of operations we multiply first:

3 x 4 = 12

Take off the 1:

Final

3b² - c³ = 11