The volume and amount of gas are constant in a tire. The initial pressure and temperature are 1.82 atm and 293 K. At what temperature will the gas in the tire have a pressure of 2.35 atm?

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

Explanation:

Step 1: Data given

The initial pressure = 1.82 atm

The initial temperature = 293 K

The pressure will be increased to 2.35 atm

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒with P1 = the initial pressure = 1.82 atm

⇒with T1 = the initial temperature = 293 K

⇒with P2 = the increased pressure = 2.35 atm

⇒with T2 = the new temperature = TO BE DETERMINED

1.82atm / 293 K = 2.35 atm / T2

T2 = 2.35 atm / (1.82 atm/293 K)

T2 = 2.35 / 0.0062116

T2 = 378 K

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

b. th3 n4zc4 pl4t3 15 c0nv3rg1ng w1th the s0uth 4m3ric4n pl4t3.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

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since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.