Consider a redox reaction for which e∘ is a negative number. part a part complete what is the sign of δg∘ for the reaction? δg∘ > 0 δg∘ < 0 submitprevious answers correct part b will the equilibrium constant for the reaction be larger or smaller than 1? will the equilibrium constant for the reaction be larger or smaller than 1? k > 1 k < 1

δg∘ will be positive so δg∘>0

and K will be negative so K<1

Explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied