A. Calculate the ratio of the translational partition functions of D2 and H2 at the same temperature and volume.

b. Calculate the ratio of the translational partition functions of xenon and helium at the same temperature and volume.

A) The ratio of the translational partition of functions D2 and H2 is : 2.82

B) The ratio of the translational partition of functions of xenon and helium is : 187.56

The formula for calculating translational partition

we rewrite equation ( 1 )

 = [ ( mass of D₂ ) / ( mass of H₂ ) ]

           = [  4.028204 amu / 2.015894 amu ]

           = 2.82

Rewriting equation ( 1 )

          = [ mass of xenon / mass of helium ]

          = [ 131.293 amu / 4.0026 amu ]

          = 187.56

Hence we can conclude that  The ratio of the translational partition of functions D2 and H2 is : 2.82  and The ratio of the translational partition of functions of xenon and helium is : 187.56

Learn more about  partition;

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.