A simple of helium measuring 6L was kept at a pressure is of 1.5 atm ,if pressure is doubled what would be its new volume ?

3L

Explanation:

The following data were obtained from the question:

V1 (original volume) = 6L

P1 (original pressure) = 1.5 atm

P2 (new pressure) = 2 x P1 ( since the new pressure is doubled)

P2 = 2 x 1.5

P2 = 3 atm

V2 (new volume) =?

Using the Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:

P1V1 = P2V2

1.5 x 6 = 3 x V2

Divide both side by 3

V2 = (1.5 x 6)/3

V2 = 3L

From our calculations, the new volume will be half the original volume and this will be 3L

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.