In the first step of glycolysis, the given two reactions are coupled. reaction 1: glucose + P i ⟶ glucose - 6 - phosphate + H 2 O Δ G = + 13.8 k J / mol reaction 2: ATP + H 2 O ⟶ ADP + P i Δ G = − 30.5 k J / mol Answer the four questions about the first step of glycolysis. Is reaction 2 spontaneous or nonspontaneous? nonspontaneous spontaneous Complete the net chemical equation. ATP + ⟶ + Calculate the overall ΔG for the coupled reaction. Δ G = kJ / mol Is the first step in glycolysis spontaneous (favorable)? no yes

Check the explanation

Explanation:

Glycolysis is the process in the field of chemistry in which a specific glucose molecule is broken down to become two or more molecules of pyruvic acid or pyruvate. The process and procedure is a metabolic multi-step pathway that happens in the cytoplasm of plant cells, animal cells, and the cells of various microorganisms.

The answer to the question above is:

1) nonspontaneous because deltaG is positive

2) glucose + ATP --> glucose-6-phosphate + ADP

3) -16.7 kJ/mol

4) yes, because deltaG is negative

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

the temperature of the gas, in k, not celsius.