For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.

(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e. g, ABC.)

1. lead fluoride (answer here )
2. aluminum hydroxide (answer here )
A. Mg(OH)2
B. BaF2
C. Ag3PO4
D. AgI

Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.

lead fluoride

aluminum hydroxide

Ksp =

Ksp =

Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.

For lead fluoride Ksp = s³

For Aluminum hydroxide Ksp = s⁴

Explanation:

The expression for the solubility product can be written as the product of the concentration of the ions present in the solution.

PbF₂ → Pb²⁺ + 2 F⁻

Then the Ksp can be written as,

Ksp = [ Pb²⁺] [F⁻]²

If the concentration can be considered as s, then the Ksp can be written as,

Ksp = s× s² = s³

For Aluminum hydroxide on dissociation it gives 4 ions as,

Al(OH)₃ → Al³⁺ + 3 OH⁻

Ksp = [Al³⁺] [OH⁻]³

      = s × s³ = s⁴

Thus,For lead fluoride Ksp = s³

For Aluminum hydroxide Ksp = s⁴

nanotechnology is a powerful tool in biomaterials research as it creates numerous possibilities for the engineering of functional molecules. nano-bio refers to projected ability to incorporate biomimicry into various materials at nanoscale.  

the answer is the first option

explanation:

just googled it m8. not that hard

lol