Information related to a titration experiment is given in the balanced equation and table below.
H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(2)
Titration Experiment Results
volume of H2SO4 (aq) used 12.0 mL
concentration of H, SO (aq)
volume of KOH(aq) used
36.0 mL
concentration of KO )
0.16 M
Based on the equation and the titration results, what is the concentration of the H2SO4(aq)?
1.
0.12 M
0.16 M
0.24 M
0.96 M

0.24M

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation above, we obtained the following information:

nA (mole of acid) = 1

nB (mole of base) = 2

Data obtained from the question include:

Va (volume of the acid) = 12mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 36mL

Cb (concentration of the base) = 0.16 M

The Ca (concentration of the acid) can be obtained as follow:

CaVa/CbVb = nA/nB

Ca x 12 / 0.16 x 36 = 1 /2

Cross multiply to express in linear form as shown below:

Ca x 12 x 2 = 0.16 x 36

Divide both side by 12 x 2

Ca = 0.16 x 36/ 12 x 2

Ca = 0.24M

Therefore, the concentration of the acid is 0.24M

i belive it is water