What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point

7.97
53.9
5390
7970

The amount of energy absorbed by water is 5390 Calories

Explanation:

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

= latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

Hence, the amount of energy absorbed by water is 5390 Calories

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