11. The following chemical equation shows the reaction between iron and chlorine.
2Fe + 3C12 --> 2FeCl3
1.12g of iron burns completely in chlorine. What is the mass of the product?
[Relative atomic mass: CI=35.5, Fe=56] *

3.25g

Explanation:

2Fe + 3C12 —> 2FeCl3

Molar Mass of Fe = 56g/mol

Mass of Fe from the balanced equation = 2 x 56 = 112g

Molar Mass of FeCl3 = 56 + (3 x 35.5) = 56 + 106.5 = 162.5g/mol

Mass of FeCl3 from the balanced equation = 2 x 162.5 = 325g

The mass of the product formed can be obtained by doing the following:

From the equation above,

112g of Fe burns in chlorine to produced 325g of FeCl3.

Therefore, 1.12g of Fe will burn in chlorine to produce = (1.12x325)/112 = 3.25g of FeCl3.

Therefore, 3.25g of the product (FeCl3) are produced.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

more infor would

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