Given the reaction 2CO + O2 = 2CO2, what is the minimum number if moles of O2 required to produce one mole of CO2?

0.5 moles of O₂

Explanation:

See the stoichiometry of the reaction:

2CO + O₂ → 2CO₂

2 moles of carbon monoxide need 1 mol of oxygen to react in order to produce 2 moles of carbon dioxide.

If I want to produce 1 mol of CO₂, I just need the half of O₂.

You will see in this rule of three. Ratio is 2:1

2 moles of CO₂ are produced by 1 mol of O₂        (Stoichiometry - reaction)

1 mol of CO₂ will be produced by ( 1 . 1) / 2 = 0.5 moles

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.