What volume is occupied by 1.892 mol of O2 at 310.5 K and 121.3 kPa?

The volume occupied is 40, 14 L

Explanation:

We use the formula PV=nRT. We convert the unit of pressure in kPa into atm.

101,325kPa1atm

121,3kPax=(121,3kPax 1 atm)/101,325kPa=1, 2 atm

PV=nRT>V=(nRT)/P

V=(1,892 mol x 0,082 l atm/K mol x 310,5K)/1, 2 atm= 40,14 L

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