A chemist prepares a solution of barium acetate BaCH3CO22 by measuring out 81.4μmol of barium acetate into a 150.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /mmolL of the chemist's barium acetate solution. Round your answer to 3 significant digits.

The answer to your question is Concentration = 0.54 mmol/L

Explanation:

Data

Barium acetate = BaCH₃CO₂

mass = 81.4 μmol

volume = 150 ml

concentration = mmol / L

Process

1.- Convert the μmol to mmol

                        1000 μmol 1 mmol

                           81.4 μmol x

                           x = (81.4 x 1) / 1000

                           x = 0.0814 mmol of BaCH₃CO₂

2.- Convert the volume to liters

                           1000 ml 1 l

                             150 ml x

                              x = (150 x 1) / 1000

                              x = 0.15 l

3.- Calculate the concentration

Concentration = 0.0814 / 0.15

                        = 0.54 mmol/L

the answer is option a.

catya that's not even a b or c