1. Why is carbon dioxide a gas at low temperatures at mars
2. How does sodium chloride combine (share) electrons
3. Name the force of attraction between metal and non-metal
4. Explain ionic compound

1. carbon dioxide is a gas at low temperatures at mars because in the oxidizing environment organic compounds are oxidized to form carbon dioxide.

2. The 1 electron in outermost shell of Na is shared with 7 electrons of outermost shell of chlorine giving neutral charge on compound.

3. Electrostatic force of attraction is between the metal and non-metal.

4. When metal and non metal exchange electrons to form a neutral or no charge compound it is said to have form ionic bonds.

Explanation:

1. Temperature at Mars is very low -80 Fahrenheit  (-60 degrees) because water is not present in the planet. Carbon dioxide is abundant in Mars. The atmosphere is oxidizing at Mars which oxidizes the organic compounds and forms carbon dioxide.

2. NaCl combines by sharing of electrons forming ionic bonding. Different atoms of the different element share electrons to form ionic bonds. Such bond is formed when electrons is transferred between the atoms. In the NaCl, Na has 1 electron (electropositive) in its outer shell and chlorine has 7 electrons (electronegative). Both share the electrons getting their octet complete and a neutral charge on the compound formed.

3. Electrostatic force of attraction is between the metal and non-metal when bond is formed. The ionic bonds is formed between metal and non metals when electron exchange takes place. The electrostatic force is the attraction between two opposite charges on the ion.

4. When a metal and non metal exchange electrons in which metal is electropositive and non metal is electronegative the bonds form is called ionic bond. The electron is transferred from metal to non metal and thus giving neutral charge on the compound i.e. the outer shell has its octet complete.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.