A 4.50 g nugget of pure gold absorbed 276 J of heat. the initial temperature was 25.0 degrees C. what was the final temperature?

500.45° C is the final temperature when a 4.50 g nugget of pure gold absorbed 276 J of heat. The initial temperature was 25.0 degrees C.

Explanation:

Data given:

q = 276 J/ grams °C (Heat absorbed)

m = 4.50 grams or

c = 0.129 joules

initial temperature  = 25 °C

Final temperature = ?

From the equation

q = m (ΔT) C  

change in temperature =

Putting the values in above simplified equation:

change in temperature =

    = 475.45 ° C.

To calculate final temperature following equation is used:

( change in temperature = final temperature- initial temperature)

475.45 + 25 = final temperature

500.45 = final temperature

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: