What is the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water

Taking into account the definition of percentage by mass, the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.35 %.

The percentage by mass expresses the concentration and is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution and multiplied by 100 to give a percentage. This is:

In this case, you know:

Replacing:

Solving:

percent by mass= 0.0835

percent by mass= 8.35 %

Finally, the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.35 %.

Learn more:

The mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.351 %.

Explanation:

Given,

Mass of Sucrose = 7.6 grams

Mass of Water = 83.4 grams

In this solution, Sucrose is solute and water is the solvent.

Mass percent of a solution can be calculated using the formula,

Mass percent =  (Mass of Solute/Mass of Solution)(100)

As sucrose is solute, mass of solute = 7.6 grams

As the solution contains both Sucrose and Water,

Mass of solution = 7.6 grams + 83.4 grams = 91 grams

Substituting the values, Mass percent = (7.6/91)(100) = 8.351 %.

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

a polar bond is formed when electrons are shared unevenly between atoms