Dibutyl succinate is an insect repellent used against household ants and roaches. Its composition is62.58% C, 9.63% H, and 27.79% O. Its experimentally determined molecular mass is 230. amu. Whatare the empirical and molecular formulas as dibutyl succinate

The molecular formula for the given organic compound is

Explanation:

We are given:

Percentage of C = 62.58 %

Percentage of H = 9.63 %

Percentage of O = 27.79 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 62.58 g

Mass of H = 9.63 g

Mass of O = 27.79 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =

Moles of Hydrogen =

Moles of Oxygen =

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.737 moles.

For Carbon =

For Hydrogen  =

For Oxygen  =

The ratio of C : H : O = 3 : 5.5 : 1

To make the ratio in a whole number we are multiplying ratio by 2, we get:

The ratio of C : H : O = 6 : 11 : 2

Step 3: Taking the mole ratio as their subscripts.

The empirical formula for the given compound is

Mass of empirical formula =

= 6(12) + 11(1) + 2(16) = 115 g/eq.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

We are given:

Mass of molecular formula = 230 g/mol

Mass of empirical formula = 115 g/mol

Putting values in above equation, we get:

Multiplying this valency by the subscript of every element of empirical formula, we get:

Thus, the molecular formula for the given compound is

so what is the problem with your lab report and whats the subject of the lab report? i will you