PLZ HELP, GIVING BRAINLIEST!!
A student prepares a solution of glucose ( C6H12O6 ) by dissolving 180.0 g of the sugar in enough water to make a 500.0 mL solution. How would the student properly label this solution?
A. 180.0 M C6H1206
B. 180.0 g/500 mL C6H12O6
C. 2.000 M C6H12O6
D. 1.000 M C6H12O6

C. 2.000 M C6H12O6

Explanation:

Let us obtain the molarity of the solution.

Molar Mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

Mass of C6H12O6 = 180g

Number of mole = Mass /Molar Mass

Number of mole of C6H12O6 = 180/180 = 1mole

Volume = 500mL = 500/1000 = 0.5L

Molarity = mole /Volume

Molarity = 1/0.5

Molarity = 2M

So the solution will be best labelled as 2M C6H12O6

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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