What is the percent yield of aluminum phosphate if a solution containing 33.4 g of sodium phosphate produced 19.6 g of aluminum phosphate when reacted with excess aluminum chloride in solution

The percent yield of aluminium phosphate in the reaction is 78.78 %

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of sodium phosphate = 33.4 g

Molar mass of sodium phosphate = 164 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of sodium phosphate and aluminium chloride is:

By Stoichiometry of the reaction:

1 mole of sodium phosphate produces 1 mole of aluminium phosphate

So, 0.204 moles of sodium phosphate will produce = moles of aluminium phosphate

Molar mass of aluminium phosphate = 122 g/mol

Moles of aluminium phosphate = 0.204 moles

Putting values in equation 1, we get:

Experimental yield of aluminium phosphate = 19.6 g

Theoretical yield of aluminium phosphate = 24.88 g

Putting values in above equation, we get:

Hence, the percent yield of aluminium phosphate in the reaction is 78.78 %

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

false

because it does not have the potential to be entirely used up