Give the set of four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Ar atom. A n = 2, l =0, m_l = 1, m_s = +\frac12 B n = 3, l =0, m_l = 1, m_s = -\frac12 C n = 3, l =1, m_l = 1, m_s = +\frac12 D n = 3, l =2, m_l = 1, m_s = -\frac12

n= 3, l= 1, ml= 1 and Ms= -1/2

Explanation:

The electronic configuration of Argon is 1S2 2S2 2P6 3S2 3P6

For the last electron in the atomic radius of Argon the principal quantum number is 3, the azimuthal quantum number is 1 representing P orbital, the magnetic quantum number is -1 for Pz suborbital while the spin quantum number is -1/2 indicating an anticlockwise direction or downward spin since the atomic number of Argon is 18.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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