What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?

The answer to your question is pH = 2.2

Explanation:

Data

pH = ?

moles of HCl = 0.927

volume = 150 l

Process

1.- Calculate the Molar concentration of HCl

Molarity = moles / volume (L)

Molarity = 0.927 / 150

              = 0.00618

2.- Calculate the pH

pH = -log [HCl]

Substitution

pH = -log [0.00618]

Result

pH = 2.2

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explanation:

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