Iodine is prepared both in the laboratory and commercially by adding Cl2(g)to an aqueous solution containing sodium iodide.2NaI(aq)+Cl2(g)⟶I2(s)+2NaCl( aq)How many grams of sodium iodide, NaI, must be used to produce 48.8 g of iodine, I2?

Hello there!

As you know, the products and reactants in a chemical reaction must be equal. Let's review the mole ratio for sodium iodide and iodine:

                                       x      =     y

                                       2              1

                                       x      =     48.8g

                                       2              1

                    1x = (48.8g *2)

                    1x = 97.6g

I hope I helped. :)

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"