A chemist prepares a solution of silver(I) nitrate AgNO3 by measuring out ×4.7102μmol of silver(I) nitrate into a 450.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /mmolL of the chemist's silver(I) nitrate solution. Be sure your answer has the correc

The concentration in /mmolL of the chemist's silver(I) nitrate solution is 0.01047 mmoles/litre.

Explanation:

Data given:

Number of moles of AgNO3 in micro mole 4.7102micromol.

The concentration is supposed to be in mmol so the micromole will be converted to milimole.

So, 1 micromole = 0.001 millimole

hence, 4.712micromole will be 0.004712 millimole.

Volume is given as 450ml which is converted into L

to convert ml into L it is divided by 1000

so 0.45 L is the volume.

Molarity or concerntration is calculated by the formula,

molarity =  

putting the values in the formula:

molarity =

              = 0.01047 mmoles/litre is the molarity of AgNO3 solution in 450 ml of solution.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

i look it up online and i'll tell you