8. Calculate the pH of 150.0 mL of H2O following the addition of 1.48 mL of 1.46 M NaOH. 12 You are correct. Your receipt no. is 158-1963 Help: Receipt Previous Tries 9. Calculate the pH of 250.0 mL of H2O following the addition of 1.49 mL of 0.99 M HCl. 2.23

12.15, 2.23

Explanation:

Using the dilution formula

C₁V₁ = C₂ V₂

where C₁ = 1.46 M

V₁  = 1.48 ml = 0.00148 L

C₂ = unknown

V₂ = 150 ml + 1.48ml = 151.48 ml = 0.15148L

1.46 M × 0.00148 L = C₂×0.15148L

C₂ = 0.0143 M

pOH = - log ( OH⁻) = - log ( 0.0143) = 1.85

pH + pOH = 14

pH = 14 - 1.85 = 12.15

b) using the same formula

C₁V₁ = C₂ V₂

C₁ = 0.99 M

V₁  = 1.49 ml = 0.00149 L

C₂ = unknown

V₂ = 250 ml + 1.49 ml = 251.49 ml = 0.25149 L

0.99 M × 0.00149 L = C₂ × 0.25149 L

C₂ = 0.00587

pH = - log ( H⁺) = - ( -2.23) = 2.23

it's c (engineer's do their work with mechanical stuff not on any living being)