375 mL of a 0.88 M potassium hydroxide solution is added to 496 mL of a 0.76 M cesium hydroxide solution. Calculate the pOH of the resulting solution.

pOH of resulting solution is 0.086

Explanation:

KOH and CsOH are monoacidic strong base

Number of moles of in 375 mL of 0.88 M of KOH = = 0.33 moles

Number of moles of in 496 mL of 0.76 M of CsOH = = 0.38 moles

Total volume of mixture = (375 + 496) mL = 871 mL

Total number of moles of in mixture = (0.33 + 0.38) moles = 0.71 moles

So, concentration of in mixture, =

Hence,