Classify the following reactions as either redox, acid-base, or precipitation. a) (cl2) + (2oh-) --> (cl-) + (clo-) + (h2o). b) already got. c) (nh3) + (h+) --> (nh4+). d) (4fe) + (3o2) --> (2fe2o3). e) (ca) + (f2) --> (caf2)

Answer :

(a) This is a redox reaction.

(c) This is an acid-base reaction.

(d) This is a redox reaction.

(e) This is a redox reaction.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Acid-base reaction : It is defined as the reaction in which an acid and base react to give salt and water as a product.

Precipitation reaction : It is defined as the reaction in which an insoluble salt formed when two aqueous solutions are combined.  The insoluble salt that settle down in the solution is known an precipitate.

(a)

This reaction is a redox reaction in which the oxidation state of Cl changes from (0) to (-1) and shows reduction and the oxidation state of Cl changes from (0) to (+1) and shows oxidation.

(c)

This reaction a an acid-base reaction in which is a base and is an acid react to give as a salt.

(d)

This reaction is a redox reaction in which the oxidation state of Fe changes from (0) to (+3) and shows oxidation and the oxidation state of O changes from (0) to (-2) and shows reduction.

(e)

This reaction is a redox reaction in which the oxidation state of Ca changes from (0) to (+2) and shows oxidation and the oxidation state of F changes from (0) to (-1) and shows reduction.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

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