If 0.38 M of an aqueous solution of magnesium nitrate hexahydrate (Mg(NO3)2 ᐧ 6H2O) was prepared in the laboratory, how many mL of the solution would you need to obtain 4.871 grams of this solute?

50 mL

Explanation:

Given data

We can find the required volume using the following expression.

M = mass of solute / molar mass of solute × liters of solution

liters of solution = mass of solute / molar mass of solute × M

liters of solution = 4.871 g / 256.41 g/mol × 0.38 mol/L

liters of solution = 0.050 L = 50 mL

1. they vary with a higher number because boiling is way hotter than melting

answer: they produce more slow than unicellular organisms.