What is the minimum amount of 6.9 M H2SO4 necessary to produce 27.8 g of H2 (g) according to the following reaction? 2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2 (g)

Answer : The minimum amount of 6.9 M needed is, 2.0 L

Explanation :

The given chemical reaction is:

First we have to calculate the moles of

Molar mass of = 2 g/mol

Now we have to calculate the moles of

From the balanced chemical reaction we conclude that,

As, 3 moles of produced from 3 moles of

So, 13.9 moles of produced from 13.9 moles of

Now we have to calculate the mass of

Thus, the minimum amount of 6.9 M needed is, 2.0 L

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