C6H5NH3Cl is a chloride salt with an acidic cation. If 46.3 g of C6H5NH3Cl is dissolved in water to make 150 mL of solution, what is the initial molarity of the cation

The initial molarity of cation is 2.38 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of = 46.3 g

Molar mass of =  129.6 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

1 mole of produces 1 mole of cation and 1 mole of anion

So, molarity of cation = (1 × 2.38) = 2.38 M

Hence, the initial molarity of cation is 2.38 M

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the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).