How many joules are needed to warm 25.5 grams of water from 14ºC to 22.5ºC? A. -8.4x103J B. 9.1 x 102J C. -9.1x102J D. 8.4x103J

B. 9.1 × 10² J  

Explanation:

The formula for the amount of heat (q) absorbed is

q = mCΔT

1. Calculate ΔT

ΔT = 22.5 °C - 14 °C = 8 °C

2. Calculate q

q₂ = mCΔT = 25.5 g × 4.184 J·°C⁻¹g⁻¹ × 8 °C = 9 × 10² J

Note: The answer can have only one significant figure, because you measured the starting temperature of the water only to the nearest degree.

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

they both have a y in them