What volume is occupied by 10.0 moles of ammonia, Nh3, at standard conditions?

10.0 moles of ammonia occupy 224 L

Explanation:

Step 1: Data given

Standard conditions:

Pressure = 1 atm

Number of moles = 1.0 moles

Volume = 22.4 L

Temperature = 273 K

gas

Step 2: Calculate vol

If 1.0 mol has a volume of 22.4 L

10.0 moles of gas has a volume of 224 L

V = (n*R*T)/p

V = (10.0 * 0.08206 * 273)/1

V = 224 L

10.0 moles of ammonia occupy 224 L

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.