How many grams of NaNO3 are there in 625.0 mL of a .325 M NaNO3 solution

The answer to your question is  17.26 g  of NaNO₃

Explanation:

Data

mass of NaNO₃ = ?

volume = 625 ml

concentration = 0.325 M

Process

1.- Convert volume to liters

       1000 ml 1 L

         625 ml  x

          x = 625 / 1000

          x = 0.625 L

2.- Find the moles of NaNO₃

     Molarity = moles / volume

solve for moles

     moles = Molarity x volume

substitution

    moles = 0.325 x 0.625

simplification

    moles = 0.203

3.- Convert moles to grams

molar mass of NaNO₃ = 23 + 14 + (16 x 3)

                                     = 85 g

         85 g 1 mol

          x       0.203

          x = (0.203 x 85) / 1

          x = 17.26 g        

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