If the initial amount of Fe(NO3)3 transferred to the cuvette is 0.026 mol, and the absorbance measurements indicate that 0.01 mol of FeSCN2 are present at equilibrium, what must be [Fe3 ] at equilibrium

Concentration of at equilibrium is 7.394 M.

Explanation:

Moles of ferric nitrate = 0.026 mol

Concentration of ferric nitrate =

1 mole of ferric nitrate gives 1 mole of ferric ions, then 12.015 M of ferric nitrate solution will have:

[Fe^{3+}]=12.015 M[/tex]

Moles of at equilbrium = 0.01 mol

Concentration of at equilbrium =

Initially

12.015 M                                0

At equilibrium

(12.015 - 4.621 )M                 4.621 M

Concentration of at equilibrium

= (12.015 - 4.621 )M = 7.394 M