The process in which an organic acid and an alcohol react to form an ester and water is known as esterification. ethyl butanoate (c3h7cooc2h5) an ester is formed when the alcohol ethanol (c2h5oh) and butanoic acid (c3h7cooh) are heated in the presence of sulfuric acid. c2h5oh(l) + c3h7cooh(l) c3h7cooc2h5(l) + h2o(l)
determine the mass of ethyl butanoate produced if 6.00 mol of ethanol is used.

696g

Explanation:

To determine the mass of ethylbutanoate produced, it is important that we know the number of moles of ethylbutanoate produced.

Now from the chemical equation, it can be seen that one mole of ethanol produces one mole of ethylbutanoate. This means that 6.0 mol of ethanol will surely produce 6.0 mol of ethylbutanoate.

Now, we need to get the mass of ethylbutanoate produced. The mass of ethylbutanoate produced is the number of moles of ethylbutanoate produced multiplied by the molar mass of ethylbutanoate produced.

The molar mass of ethylbutanoate is 12(6) + 12(1) + 16(2) = 116g/mol

The mass thus produced is 116 * 6 = 696g

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"