If the tropospheric concentrations of oh and cf3ch2f are 8.1×105 and 6.3×108 molecules/cm3, respectively, what is the rate of reaction at this temperature in m/s? express the rate in molarity per second to two significant figures.

2.3*10^-19 M/s

Explanation:

Generally, reaction rate is the product of the rate constant, and the concentrations of the reactants in the system. Therefore, the rate of the reaction can be expressed as:

rate = k*

The value of the rate constant k is 1.6*10^8 [1/(M*s)] at the given temperature.

= 6.3*10^8 molecules/cm^3

= 8.1*10^5 molecules/cm^3.

However, we need to convert to mol/(L(M). Therefore:

6.3*10^8 *(1000/6.023*10^23) = 1.05*10^-12

8.1*10^5 molecules/cm^3 *(1000/6.023*10^23) = 1.3*10^-15

Thus:

rate =k* = 1.6*10^8* 1.05*10^-12* 1.3*10^-15 =2.3*10^-19 M/s

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.