Which statement best describes the light that will cause emission of electrons from a given metal through the photoelectric effect?
light with any intensity below a certain frequency
light with any intensity above a certain frequency
light with any frequency below a certain intensity
light with any frequency above a certain intensity

The correct (b) light with any intensity above a certain frequency

The explanation:

when Energy of a photon : E = hf

- The photoelectric effect works like this:

- If you shine light of high enough energy on to a metal, electrons will be emitted from the metal. Light below a certain threshold frequency, no matter how intense, will not cause any electrons to be emitted. Light above the threshold frequency, even if it's not very intense, will always cause electrons to be emitted.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

yes

ya te ayud espera