For Aequals=[Start 3 By 2 Matrix 1st Row 1st Column 1 2nd Column 2 2nd Row 1st Column 1 2nd Column negative 1 3rd Row 1st Column 1 2nd Column 1 EndMatrix ]1 2 1 −1 1 1 and bequals=[Start 3 By 1 Matrix 1st Row 1st Column 2 2nd Row 1st Column 10 3rd Row 1st Column 0 EndMatrix ]2 10 0 , a least-squares solution of Axequals=b is ModifyingAbove Bold x with caretxequals=[Start 2 By 1 Matrix 1st Row 1st Column 6 2nd Row 1st Column negative 3 EndMatrix ]6 −3 . Compute the least-squares error associated with this solution.

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478

n=1.75+1.75

step-by-step explanation:

3.5/2=1.75

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.