The half life for the first order conversion of a to b is 56.6 hours. how long does it take for the concentration of a to decrease 10.0% of its original concentration

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

A → B

Initial concentration of the reactant = x

Final concentration of reactant = 10% of x = 0.1 x

Time taken by the sample, t = ?

Formula used :

where,

= initial concentration of reactant

A = concentration of reactant left after the time, (t)

= half life of the first order conversion  = 56.6 hour

= rate constant

Now put all the given values in this formula, we get

t = 188.06 hour

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

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explanation:  

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