Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 21.1 and the temperature is 37.0 ° c ? δ g ° ' for the reaction is − 16.7 kj/mol . δ g = kj / mol

Answer : The value of is -8.84 kJ/mol

Explanation :

The formula used for is:

   ............(1)

where,

= Gibbs free energy for the reaction  = ?

=  standard Gibbs free energy  = -16.7 kJ/mol

R = gas constant =

T = temperature =

Q = reaction quotient = = 21.1

Now put all the given values in the above formula 1, we get:

Therefore, the value of is -8.84 kJ/mol

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

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