Express the concentration of a 0.0350 m aqueous solution of fluoride, f − , in mass percentage and in parts per million (ppm). assume the density of the solution is 1.00 g/ml. a. number in percentage %
b. number in ppm .

Answer :

(a) The mass percentage is 0.0665 %

(b) The concentration in ppm is 665 ppm.

Explanation :

Part (a) :

As we are given that, 0.0350 M aqueous solution of fluoride ion that means 0.0350 moles of fluoride ion present in 1 L of solution.

First we have to calculate the mass of fluoride ion.

Molar mass of = 19 g/mole

Now we have to calculate the mass of solution.

Mass of solution = Density of solution × Volume of solution

Density of solution = 1.00 g/mL

Volume of solution = 1 L = 1000 mL

Mass of solution = 1.00 g/mL × 1000 mL

Mass of solution = 1000 g

Now we have to calculate the mass -percentage.

Thus, the mass percentage is 0.0665 %

Part (b) :

Parts per million (ppm) : It is defined as the mass of a solute present in one million parts by the mass of the solution.

Now we have to calculate the concentration in ppm.

Thus, the concentration in ppm is 665 ppm.

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