The synthesis of methanol from carbon monoxide and hydrogen gas is described by the following chemical equation: co(g)+2h2(g)⇌ch3oh(g) the equilibrium constant for this reaction at 25 ∘c is kc=2.3×104. in this tutorial, you will use the equilibrium-constant expression to find the concentration of methanol at equilibrium, given the concentration of the reactants. determine the expression for the equilibrium constant, kc, for the reaction by identifying which terms will be in the numerator and denominator.

Explanation:

Let's consider the following reaction.

CO(g) + 2 H₂(g) ⇌ CH₃OH(g)

The equilibrium constant (Kc) is the products of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.

If you wanted to calculate [CH₃OH], suppose that the molar concentrations for CO and H₂ at equilibrium are [CO] = 0.04 M and [H₂] = 0.08 M. The concentration of methanol at equilibrium is:

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.