Action balanced equation particle view (center of

screen)

steps you took to make the
equation balanced

make
ammoni
a n 2 + h 2  nh 3

separate
water

h 2 o  h 2 + o 2

combust
methane

ch 4 + o 2
 co 2 + h 2

N₂ + 3H₂  →  2NH₃

2H₂O →  2H₂ + O₂

CH₄ + 2O₂  →  CO₂ + 2H₂O

Explanation:

A) Make ammonia:

Chemical equation:

N₂ + H₂  →  NH₃

Balanced chemical equation:

N₂ + 3H₂  →  2NH₃

Step one:

N₂   +   H₂      →     NH₃

N = 2                    N = 1

H = 2                    H = 3

Step 2:

N₂   +   3H₂      →          2NH₃

N = 2                              N = 1

H = 2×3 = 6                    H = 3×2 = 6

Step 3:

N₂   +   3H₂      →          2NH₃

N = 2                              N = 1×2 = 2

H = 2×3 = 6                    H = 3×2 = 6

B) separate water:

Chemical equation:

H₂O →  H₂ + O₂

Balanced chemical equation:

2H₂O →  2H₂ + O₂

Step one:

H₂O        →        H₂ + O₂

H = 2                    H = 2

O = 1                     O = 2

Step 2:

2H₂O                →        H₂ + O₂

H = 2×2 = 4                  H = 2

O = 1×2 =2                     O = 2

Step 3:

2H₂O                →        2H₂ + O₂

H = 2×2 = 4                  H = 2×2 = 4  

O = 1×2 =2                     O = 2

C) Combust methane

Chemical equation:

CH₄ + O₂  →  CO₂ + H₂O

Balanced chemical equation:

CH₄ + 2O₂  →  CO₂ + 2H₂O

Step one:

CH₄ + O₂  →  CO₂ + H₂O

C = 1                    C = 1

H = 4                   H = 2

O = 2                    O = 3

Step 2:

CH₄ + 2O₂  →  CO₂ + H₂O

C = 1                     C = 1

H = 4                    H = 2

O = 2×2 = 4          O = 3

Step 3:

CH₄ + 2O₂  →  CO₂ + 2H₂O

C = 1                    C = 1

H = 4                   H = 2×2 = 4  

O = 2×2 = 4         O = 2 + 2 = 4

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.